Today's Logic Puzzle

by Farkel 28 Replies latest jw friends

  • Seeker
    Seeker
    1/2 of the number of Jerks who are not Elders or Ministerial Servants are Pedophiles.

    People are keying on that sentence and answering 8 1/2. But the question was not how many people are covered by that sentence, but:

    How many Pedophiles are there in that Circuit?
    Cannot tell from the data provided. The sentence above covers part of the pedophile population. Then you have to add the unknown number of pedophile publishers. And the unknown number of Non-Jerk elders and M.S. who are pedophiles.

    Just like in real life Watchtower-land, the actual number of pedophiles is unknown but substantial.

  • Scully
    Scully

    If we understand the nature of pedophiles would automatically categorize such ones as Jerks, then the answer of 8.5 pedophiles in the circuit would be correct.

    Love, Scully


    In the desert things find a way to survive. Secrets are like this too. They work their way up through the sands of deception so men can know them. - The X Files

  • Seeker
    Seeker

    Indeed, Scully, I did think of that, and that is possibly what Farkel had in mind even though the definitions of 'jerk' and 'pedophile' do not dovetail perfectly, though one is a subset of the other. But that still leaves out all the ordinary publisher pedophiles, so 8.5 is probably incorrect.

  • JanH
    JanH

    Seeker,

    Farkel prohibited me from posting in this thread , but I got the same conclusion as you. We don't have enough information.

    - Jan
    --
    - "How do you write women so well?" - "I think of a man and I take away reason and accountability." (Jack Nicholson in "As Good as it Gets")

  • aChristian
    aChristian

    Since this is a logic problem, I'll say nine. After all, someone can't be just partly a pedophile. That's like being sort of pregnant. Either you are or you are not. I believe mental health professionals now tell us that pedophilia is not a curable mental illness. That being the case, there are no "former pedophiles" or "slight pedophiles." So a half in this case equals a whole. So, I'll say nine.

  • expatbrit
    expatbrit

    I'd tell you but it would preach clergy privelege.

    Expatbrit

  • ladonna
    ladonna

    Dipfark

    I declare you the master of nuttiness!!!!
    There is no answer, just all of us idiots sitting studiously trying to do our math.......

    You Rougue
    Ana

  • gravedancer
    gravedancer

    The question allows people to key off the fact that there are 80 jerks in the circuit based on the fact that 1/2 of all the jerks are elders and all the elders are jerks. Therefore, if there are 40 elders then there are 80 jerks in the circuit.

    If Half of the Ministerial Servants (1/2 of 46) are jerks then 23 Ministerial Servants are jerks too.

    So 40 Elders + 23 Ministerial Servants gives 63 jerks. That means there are 17 Jerks who are not either Ministerial Servamts or Elders.

    1/2 of that remaining number of Jerks are Pedophiles – thus giving you 8½ jerks who are pedophiles.

    So the important question (which I think has an obvious answer) is are all Pedophiles Jerks?

    The obvious answer is 8/12. But since it is impossible to have half a person, according to Farkel you must be one “jerk off”!!!!!

  • Hmmm
    Hmmm

    I just saw the earlier puzzle a few days ago, and it's been bugging me. But the answer doesn't make sense--to me, anyway.

    The series was:
    10 11 12 13 14 15 16 17 20 22 24 31 200 10011 100000000

    And the solution was: "All of the numbers in the sequence were base representations of the same number. The last number in the sequence was a representation of the number in binary. The next to the last number was in base 3, second-next-to-last number was in base 4, and so forth."

    10[16]=16
    11[15]=16
    12[14]=16
    13[13]=16
    14[12]=16
    15[11]=16
    16[10]=16
    17[9]=16
    20[8]=16
    22[7]=16
    24[6]=16
    31[5]=16
    200[4]=16 (though, wouldn't 40 be the MORE correct answer?)
    10011[3]=85 (shouldn't 16 be 51?)
    100000000[2]=256 (shouldn't 16 be 10000?)

    Where did I go wrong?

    Hmmm

  • teejay
    teejay

    Cellomould, with an assist from Seeker, is correct.

    Your query is (purposely?) flawed. You don't present enough information to solve it. That's your point.

    The answer to the question "How many are there" is "who knows?"

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