I looked at the canopy coming down problem. how high was it, as imagined? a hemispheric dome firmament over a flat earth?
Why would it be a hemisphere over a flat earth?
6000 km high? or more conservatively estimated at satelite orbit heights?
Satellites orbit anywhere from 2000 to over 35000 km.
Than it would take 1 million joules to put a kilo up there.
Please show your math. Also, you really didn't define what you mean by "up there".
4184 joules will heat that kilo 1 degree c. (1kcalory). so: upon falling the mass of the water canopy, would have been heated to 240 degrees c. superheated steam.
Please show that math and explain those numbers. I am curious how super-heated steam falls like rain, also. And how you now claim super-heated steam but earlier claimed the air would be a nice temperature.
I re-did the atmosphere at the new sea level above Everest, and the fall in pressure is equivalent to the change in a 3 story climb, do not expect adiabatic cooling from that. how is that math?
Please show that math.
Earth circumference 40 000 km. added heights 8 850km to radius X 2 ( to get diameter) =17.7km x 3,14= 55.6 km added to diameter. 40 000:55.6=~ 720. --.14 % --addiing a slice of ~56 km longditude to the existing atmosphere reduces the density by only .14%.
What us 8850 km in that equation? The height of Everest? Show the math showing the lessening of atmospheric density. Also, Everest is 8848 METERS high, not kilometers.
Numbers count.
So far, you've not shown that you can. Please show your work and explain it. You're continually mixing concepts and throwing out numbers without context or that don't make sense.